# Line slope calculator 5x+6y=63

**Straight line given by points A[3; 8] and B[9; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.8333x+10.5

**Canonical form of the line equation:**5x+6y-63 = 0

**Parametric form of the line equation:**

x = 6t+3

y = -5t+8 ; t ∈ R

**Slope:**m = -0.8333

**Slope angle of line: φ =**-39°48'20″ = -0.6947 rad

**X intercept:**x

_{0}= 12.6

**Y intercept:**y

_{0}= q = 10.5

**Distance line from the origin:**d

_{0}= 8.0663

**The length of the segment AB: |AB| =**7.8102

**Vector: AB =**(6; -5)

**Normal vector: n =**(5; 6)

**Midpoint of the segment AB: M =**[6; 5.5]

**Perpendicular Bisector equation:**6x-5y-8.5 = 0

**Vector OA = (3; 8) ; |OA| = 8.544**

**Vector OB = (9; 3) ; |OB| = 9.4868**

**Scalar product OA .OB = 51**

**Angle ∠ AOB = 51°32″ = 0.8903 rad**