# Line slope calculator 5x-3y=-5

**Straight line given by points A[2; 5] and B[5; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.6667x+1.6667

**Canonical form of the line equation:**5x-3y+5 = 0

**Parametric form of the line equation:**

x = 3t+2

y = 5t+5 ; t ∈ R

**Slope:**m = 1.6667

**Slope angle of line: φ =**59°2'10″ = 1.0304 rad

**X intercept:**x

_{0}= -1

**Y intercept:**y

_{0}= q = 1.6667

**Distance line from the origin:**d

_{0}= 0.8575

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; 5)

**Normal vector: n =**(5; -3)

**Midpoint of the segment AB: M =**[3.5; 7.5]

**Perpendicular Bisector equation:**3x+5y-48 = 0

**Vector OA = (2; 5) ; |OA| = 5.3852**

**Vector OB = (5; 10) ; |OB| = 11.1803**

**Scalar product OA .OB = 60**

**Angle ∠ AOB = 4°45'49″ = 0.0831 rad**